EE3755 Verilog Homework 2 Due: 31 October,2003
/// 
Solve this problem by modifying a copy
of
http://www.ece.lsu.edu/alex/EE3755/fall03/hw02.v
    Problem 0 :copy the homework template into a subdirectory named hw in your class account.
                         The file name should be hw02.vType your account and name.
  module hello_it_is_me();
       $display(“My account, My name\n”); //just type your account and name    endmodule  Problem 1
  module find_character_c(character_count,v,character_in);
   input [31:0] v;   input  [7:0] character_in;   output [1:0] character_count;endmodule You are given two inputs.Input v contains 4 characters.Input character_in contains ASCII character value.But you should check only for upper case letter.You have to count how many times the upper case letter appears in input v. For example) Case 1:When character_in  65  = 01000001(ASCII for “A”);And v = 01000001 01000001 00000000 00000000The output character_count should be 2// because “A” appears twice. Case 2:But When character_in 128 =1000 0000 //this is not a letter.And v = 1000 0000 1000 0000 1000 0000 0000 0000The output character_count should be 0 because character_in is not a letter.//the range of ASCII value for letters are from 65(“A”) to 90(“Z”). Case 3:When character_in  65  = 01000001(ASCII for “A”);And v = 00100000101000001000000000000000Do not interpret this as 0 01000001 01000001 00000000 0000000
 The output character_count should be 0.    /////////////////////////////////////////////////////////////////////////////////// Problem 2
///module find_character_s(character_count, character_bit_in,character_in,clk,start);
   input character_bit_in;   input  [7:0] character_in;   input clk;   input start;   output [4:0] character_count;   aways @( posedge clk)      begin         if(start)            begin              //do something here            end    // Solution goes here.   endmodule This is serial version of module find_character_c.1-bit input character_bit_in will be available at every new clk input.Input character_in contains ASCII character value.start follow definition of the class notes. Character_count should be updated at every 8 clk cycles.Pay attention to the length of character_count.It is 5 bits now.   But you should check only for upper case letter.You have to count how many times the upper case letter appears in input v. For example) Case 1:When character_in  65  = 01000001(ASCII for “A”);And v = 01000001010000010000000000000000The output character_count should be 1 after certain number of cycles// because “A” appears.The output character_count  should be 2 after certain number of cycles// because second “A”appears.  Case 2:But When character_in 128 =1000 0000 //this is not a letter.And v = 1000 0000 1000 0000 1000 0000 0000 0000The output character_count should be 0 because character_in is not a letter.//the range of ASCII value for letters are from 65(“A”) to 90(“Z”). Case 3:When character_in  65  = 01000001(ASCII for “A”);And v = 00100000101000001xxxxxxxxxxxxxxxxxxxxxxxxxxxDo not interpret this as 0 01000001 01000001
The output character_count should be 0.//about the start input..0100000000000000000000000  (start input)xx01000001xxxxxxxxxxxxxxx  (character_bit_in input)When character_in = 65,Character_count should be 1 after certain number of clk cylces.